# 8.2.2 Basic Measurements, PT3 Practice

               
Question 6:
 
The mass of a box containing 6 papayas is 21.32 kg. The mass of the box when it is empty is 1.46 kg.
 Calculate the average mass, in g, of a papaya.
 
 Solution:
 
Mass of 6 papayas
 = 21.32 – 1.46
 = 19.86 kg
 
 Average mass of a papaya
 = 19.86 ÷ 6
 = 3.31 kg
 = 3.31 × 1000 g
 = 3310 g
 

 
 
 
              
Question 7:
 Louis bought 600 g of cookies. Dennis bought twice the mass of cookies that Jackson bought. They bought 1.35 kg of cookies altogether. Calculate the mass, in g, of cookies bought by Jackson.
 
 Solution:
 
Let Jackson bought w g of cookies.
 600 g + 2 × w + w = 1.35 kg
 600 g + 3w = 1.35 kg
 600 g + 3w = 1350 g
 3w = 1350 g – 600 g
 w = 750 g ÷ 3
 w = 250 g
 

 
 
 
         
Question 8:
 If the mass of 4 packets of candies is 2.6 kg, what is the mass of 9 packets of the same candies, in kg?
 

 Solution:
        
 
      
Question 9:
 
It is given that $\frac{1}{4}$ of fruits is supplied to Juice Stall A and $\frac{2}{7}$   to Juice Stall B. The remaining 133.25 kg is sold to a fruit stall.
 Calculate the mass of fruits that has been supplied to Fruit Stall B.
 
 Solution:
   
 
 
Question 10:
The mixture of metal to produce a piece of 50 sen coin are and the rest is copper.
If the mass of copper is 1.6 g, find the total mass, in g, of zinc and nickel.

Solution: