Bab 14 Pengamiran

$\begin{array}{l}\text{(a) }{\displaystyle {\int }_{-1}^0\left(3x^2-2x+5\right)dx}\\ ={\left[\frac{3x^3}{3}-\frac{2x^2}{2}+5x\right]}_{-1}^0\\ ={\left[x^3-x^2+5x\right]}_{-1}^0\\ =0-\left[{\left(-1\right)}^3-{\left(-1\right)}^2+5\left(-1\right)\right]\\ =0-\left(-1-1-5\right)\\ =7\end{array}$

$\begin{array}{l}\text{(b) }{\displaystyle {\int }_0^2{\left(2x+1\right)}^{3}dx}\\ ={\left[\frac{{\left(2x+1\right)}^4}{4\left(2\right)}\right]}_0^2\\ ={\left[\frac{{\left(2x+1\right)}^4}{8}\right]}_0^2\\ =\left[\frac{{\left(2\left(2\right)+1\right)}^4}{8}\right]-\left[\frac{{\left(2\left(0\right)+1\right)}^4}{8}\right]\\ =\frac{625}{8}-\frac{1}{8}\\ =78\end{array}$