4.2.2 Decimals, PT3 Practice


Question 5:
Calculate the value of 45+15.4÷4 and express the answer correct to one decimal place. 

Solution:
45+15.4÷4=45+3.85=0.8+3.85=4.65=4.7 (one decimal place)


Question 6:
Calculate the value of 84 – 3(14 + 48 ÷ 6) =

Solution:
843(14+48÷6)=843[14+(48÷6)]=843(14+8)=843(22)=8466=18


Question 7:
Calculate the value of 4×0.180.9.

Solution:
4×0.180.9=0.720.9            =0.72×100.9×10            =7.29            =0.8


Question 8:
Calculate the value of (8.42.64)÷43 and express the answer correct to two decimal places.

Solution:
(8.42.64)÷43=5.761.44×34=4.32

4.2.1 Decimals, PT3 Practice


Question 1:
62.4 – 36.02 + 12.6 =

Solution:



Question 2:
4.76 × 7.2 ÷ 0.3 =

Solution:
4.76×7.2÷0.3=34.272÷0.3=34.2720.3=34.272×100.3×10=342.723=114.24





Question 3:
0.12 × (5.9 – 1.33) ÷ 0.8 =

Solution:
0.12×(5.91.33)÷0.8=0.12×4.57÷0.8=0.5484÷0.8=0.54840.8=0.5484×100.8×10=5.4848=0.6855




Question 4:
14.83 + (20.04 – 10.68) ÷ 1.8 =

Solution:
14.83+(20.0410.68)÷1.8=14.83+9.36÷1.8=14.83+9.36×101.8×10=14.83+93.618=14.83+5.2=20.03



3.2.3 Fractions, PT3 Practice



Question 11
:
Table below shows the types of fruit tree planted by Azmi in his orchard.


(a) Calculate the number of guava trees.
(b) 100 mangosteen trees died due to fungus.
Find the total number of the remaining trees.

Solution:
(a)
Number of Guava trees=13×180=60

(b)

Number of mangosteen and guava trees=180+60=240Fraction of mangosteen and guava trees=35Total number of trees=53×240=400Total number of remaining trees=400100=300

Question 12:
A palm oil processing factory has a number of workers. 47 of the workers are skilled workers. If 35 of the general workers are 18 females, find the total number of workers in the factory.

Solution:
35 of the general workers are 18 females.Let the number of general workers =w35×w=18     w=18×53        =30Hence the total number of workers in the factory=30÷(7747)=30÷37=30×73=70

Question 13:
In a fruit basket, 25 are mangoes and the rest are kiwis.
If 23 of the mangoes or 12 of them are in good condition, calculate the number of kiwis in the basket.

Solution:
Let the number of mangosin the basket=x23×x=12x=12×32x=18 mangoesTotal number of mangoes and kiwis in the basket=18×52=45Hence, the number of kiwisin the basket=(125)×45=(5525)×45=35×45=27


3.2.2 Fractions, PT3 Practice


Question 6:
112÷14×45=

Solution:
112÷14×45=32×421×45=245=445


Question 7:
415÷116×229=

Solution:
415÷116×229=2135×627×20493=8


Question 8:
234×113÷713=

Solution:
234×113÷713=114×43÷223=114×43×3222=12


Question 9:
456213÷59=

Solution:
456213÷59=456(73÷59)=456(73×935)=456215=456415=2530630=1930


Question 10:
(79+1115)÷(7815415)=

Solution:
(79+1115)÷(4815315)=(3545+3345)÷(48153315)=6845÷1515=6845÷113=6845÷43=68174515×34=1715=1215

3.2.1 Fractions, PT3 Practice


Question 1:
325+15615=

Solution:
325+15615=31230+12530630=43730630=43130=5130


Question 2:
6112323156=

Solution:
6112323156=6112381211012=(513123812)11012=251211012=1171211012=712


Question 3:
30(27÷221)=

Solution:
30(27÷221)=30(27×2132)=303=27


Question 4:
(712323)×1269=

Solution:
(712323)×1269=(736346)×1269=(696346)×1269=356×1269=236×122693=23


Question 5:
115÷(4212)=

Solution:
115÷(4212)=115÷(322212)=65÷(112)=65÷32=625×23=45