2.2.1 Squares, Square Roots, Cube and Cube Roots, PT3 Practice 1
Question 1:
Calculate the values of the following:
(a)√5098(b)√11764(c)√81−√0.01(d)√3.24
Solution:
(b)√11764=√8164=98=118
(c)√81−√0.01=9−√1100=9−110=9−0.1=8.9
(d)√3.24=√324100=√3625=√8125=95=145
Question 2:
Calculate the values of the following:
(a)3√16250(b)3√−4256(c)3√0.008(d)3√0.729
Solution:
(b)3√−4256=3√−164=−14
(c)3√0.008=3√81000=210=0.2
(d)3√−0.729=3√−7291000=−910=−0.9
Question 3:
Find the value of
3√338+√21425.
Solution:
Question 4:
Find the values of the following:
(a) 1 – (–0.3)3.
(2.1÷3√27)2
(b)
Solution:
(a)
1 – (–0.3)3 = 1 – [(–0.3) × (–0.3) × (–0.3)]
= 1 – (–0.027)
= 1 + 0.027
= 1.027
(b)
(2.1÷3√27)2=(2.1÷3)2=(0.7)2=0.49
Question 5:
Find the values of the following:
(a)(9+3√−8)2(b)√144÷3√216×0.33
Solution:
(b)√144÷3√216×0.33=144÷6×(0.3×0.3×0.3)=24×0.027=0.648