4.2.1 Linear Equations I, PT3 Practice 1


4.2.1 Linear Equations I, PT3 Practice 1
Question 1:
Solve the following linear equations.
  (a)  4 – 3n = 5n – 4   
  (b) 4m210+m=12  

Solution:
(a)
4 – 3n = 5n – 4   
–3n –5n = – 4 – 4   
–8n = – 8   
 8n = 8
n = 8/8 = 1
 
(b)4m210+m=122(4m2)=10+m8m4=10+m8mm=10+47m=14m=147m=2


Question 2:
Solve the following linear equations.
(a)x3=4x(b)3(x2)5=9
 
Solution:
(a)x3=4xx=3(4x)x=123xx+3x=124x=12x=124x=3

(b)3(x2)5=93(x2)=9×53x6=453x=45+63x=51x=513x=17



Question 3:
Solve the following linear equations.
(a)3m4+15=9(b)2m+8=3(m2)

Solution:
(a)3m4+15=93m4=9153m4=63m=6×43m=24m=243m=8
 
(b)2m+8=3(m2)2m+8=3m62m3m=68m=14m=14


Question 4:
Solve the following linear equations.
(a)11+2x3=9(b)x53=x6

Solution:
(a)11+2x3=92x3=9112x3=22x=6x=62x=3
 
(b)x53=x66(x5)=3x6x30=3x6x3x=303x=30x=10


Question 5:
Solve the following linear equations.
(a) 4(2x3)=24(b)y2y+43=5

Solution:

(a) 4(2x3)=248x12=248x=24+128x=36x=368x=412
 
(b)y2y+43=5y×32×32(y+4)3×2=53y2(y+4)6=53y2y8=30y=30+8y=38