4.2.1 Linear Equations I, PT3 Practice 1
Question 1:
Solve the following linear equations.
(a) 4 – 3n = 5n – 4
(b)
4m−210+m=12
Solution:
(a)
4 – 3n = 5n – 4
–3n –5n = – 4 – 4
–8n = – 8
8n = 8
n = 8/8 = 1
(b)4m−210+m=122(4m−2)=10+m8m−4=10+m8m−m=10+47m=14m=147m=2
Question 2:
Solve the following linear equations.
(a)x3=4−x(b)3(x−2)5=9
(a)x3=4−x(b)3(x−2)5=9
Solution:
(b)3(x−2)5=93(x−2)=9×53x−6=453x=45+63x=51x=513x=17
Question 3:
Solve the following linear equations.
(a)3m4+15=9(b)2m+8=3(m−2)
Solution:
(a)3m4+15=93m4=9−153m4=−63m=−6×43m=−24m=−243m=−8
(b)2m+8=3(m−2)2m+8=3m−62m−3m=−6−8−m=−14m=14
Question 4:
Solve the following linear equations.
(a)11+2x3=9(b)x−53=x6
Solution:
(a)11+2x3=92x3=9−112x3=−22x=−6x=−62x=−3
(b)x−53=x66(x−5)=3x6x−30=3x6x−3x=303x=30x=10
Question 5:
Solve the following linear equations.
(a) 4(2x−3)=24(b)y2−y+43=5
Solution:
(a) 4(2x−3)=248x−12=248x=24+128x=36x=368x=412
(b)y2−y+43=5y×32×3−2(y+4)3×2=53y−2(y+4)6=53y−2y−8=30y=30+8y=38