Long Questions (Question 2)


Question 2:
In the diagram, PRS and QRT are straight lines. Given is the midpoint of PS and
QR : RT = 1 : 3, Find
(a) the coordinates of R,
(b) the coordinates of T,
(c) the coordinates of the point of intersection between lines PQ and ST produced.


Solution:
(a)
Given R is the midpoint of PS.
R = ( 3 + 7 2 , 2 + 6 2 ) R = ( 5 ,   4 )

(b)
Q R : R T = 1 : 3 Lets coordinates of  T = ( x ,   y ) ( ( 1 ) ( x ) + ( 3 ) ( 4 ) 1 + 3 , ( 1 ) ( y ) + ( 3 ) ( 5 ) 1 + 3 ) = ( 5 ,  4 ) x + 12 4 = 5 x + 12 = 20 x = 8 y + 15 4 = 4 y + 15 = 16 y = 1 T = ( 8 ,   1 )

(c)
Gradient of  P Q = 5 2 4 3 = 3 Equation of  P Q , y 2 = 3 ( x 3 ) y 2 = 3 x 9 y = 3 x 7 ( 1 ) Gradient of  S T = 6 1 7 8 = 5 Equation of  S T , y 1 = 5 ( x 8 ) y 1 = 5 x + 40 y = 5 x + 41 ( 2 )
 
Substitute (1) into (2),
 3x – 7 = –5x + 41
 8x = 48
 x = 6

 From (1),
 y = 3(6) – 7 = 11 

The coordinates of the point of intersection between lines PQ and ST = (6, 11).