7.2.2 Algebraic Formulae, PT3 Practice


Question 6:
Given 2ab=3ab22. Express a in terms of b.

Solution:
2ab=3ab223a2ab=b22a(32b)=b22a=b22(32b)


Question 7:
Given a=b+1a. Express b in terms of a.

Solution:
a=b+1ab+1=a2[(b+1)12]2=(a2)2b+1=a4b=a41


Question 8:
Given x=5w2wy.(i) Express w in terms of x and y.(ii) Find the value of w when x=10 and y=15.

Solution:
(i)x=5w2wy2wxxy=5w2wx5w=xyw(2x5)=xyw=xy2x5(ii)w=(10)(15)2(10)5  =15015  =10


Question 9:
Azmin is h years old. His father is twice his brother’s age. If Azmin is 3 years older than his brother, write a formula for the sum (S) of their age.

Solution:
Azmin’s age = h
Azmin’s brother’s age = h – 3
Azmin’s father’s age = (h – 3) × 2 = 2h – 6

Therefore, the sum (S) of their age
S = h + (h – 3) + (2h – 6)
S = h + h – 3 + 2h – 6
S = 4h – 9


Question 10:
Mei Ling is 12 years older than Ali. In the next four years, Raju will be two times older than Ali. If h represents Ali’s age, write the algebraic expressions that represent the total of their ages, in terms of h, in four years time.

Solution:
Ali’s age in the next four years = h + 4
Mei Ling’s age = (h + 4) + 12 = h + 16
Raju’s age = (h + 4) × 2 = 2h + 8

Therefore, the total (S) of their age
S = (h + 4) + (h + 16) + (2h + 8)
S = 4h + 28

7.2.1 Algebraic Formulae, PT3 Practice


7.2.1 Algebraic Formulae, PT3 Practice
 
Question 1:
Given m2+ 7 = k, express m in terms of k.

Solution:
m2+7=km2=k7m=k7

  


Question 2:
Given 5km = mn – 2k, express k in terms of m and n.

Solution:
5km=mn2k5km+2k=mnk(5m+2)=mnk=mn5m+2

 


Question 3:
Given 2km2n=m , express m in terms of k and n.

Solution:
2km2n=mmm2n=2km+m2n=2k2nm+m2n=2km(2n+1)2n=2km=4kn2n+1


Question 4:
Given 4mTk=3hm  , express T in terms of h and m.

Solution:
4mTk=3hm4m2=3hT3hk3hT=4m2+3hkT=4m2+3hk3hT=(4m2+3hk3h)2Square both sides



Question 5:
Given 8s3h4=2 , express s in terms of h.

Solution:
8s3h4=28s3h4=4Square both sides8s3h=168s=16+3hs=16+3h8s=2+3h8


7.1 Algebraic Formulae


7.1 Algebraic Formulae

7.1.1 Variables and Constant
1. A variable is a quantity without a fixed value.
2. A constant is a quantity with a fixed value.


7.1.2 Concept of Formulae
1. An algebraic formula is an equation which shows the relationship between several variables and/ or constant.
2. The subject of an algebraic formula is a linear variable expressed in terms of the other variables.

Example 1:
Express x in terms of y, if y=23xx.  

Solution:
y=23xxxy=23xxy+3x=2x(y+3)=2x=2y+3

Example 2:
Given that s=p2q22u, make p the subject of the formula.

Solution:
s=p2q22r2rs=p2q2p2=2rs+q2p=2rs+q2