Example 7 (Comparison Method)
Given that f:x→2hx−3k , x≠3k , where h and k are constants and f−1:x→14+24xx , x≠0, find the value of h and of k.
Solution:
Given that f:x→2hx−3k , x≠3k , where h and k are constants and f−1:x→14+24xx , x≠0, find the value of h and of k.
Solution:
