# 1.2.3 Whole Numbers, PT3 Practice

      
Question 11:
 Britney rents a stall to sell cakes. The rental of the stall is RM500 per month. The cost for baking a cake is RM5 per box and she sells it at RM10 per box. What is the minimum box of cakes must Britney sell each month to make a profit?
 
 Solution:
 
Rental of the stall = RM500 monthly
 Cost of baking a cake per box = RM5
 Selling price per box = RM10
 Profit per box
 = RM10 – RM5
 = RM5
 
 The number of boxes of cakes to accommodate the cost
 = RM500 ÷ RM5
 = 100
 
 Hence, the minimum box of cakes must Britney sell each month to make a profit = 101
 
 
 
 

# 1.2.2 Whole Numbers, PT3 Practice

Question 6:
Solve 4 (8 + 14)(37 – 18) + 46

Solution:
4 (8 + 14)(37 – 18) + 46
= 4(22)(19) + 46
= 4 × 22 × 19 + 46
= 1672 + 46
= 1718

Question 7:
Calculate the value of
113 + 6(47 – 4 × 9)

Solution:
113 + 6(47 – 4 × 9)
= 113 + 6[47 – (4 × 9)]
= 113 + 6(47 – 36)
= 113 + 6(11)
= 113 + 66
= 179

Question 8:
Solve 128 + (9 × 4) – 318 ÷ 6

Solution:
128 + (9 × 4) – 318 ÷ 6
= 128 + 36 – 53
= 164 – 53
= 111

Question 9:
Calculate the value of
62 × 15 – 40 + 68 ÷ 17.

Solution:
(62 × 15) – 40 + (68 ÷ 17)
= 930 – 40 + 4
= 894

Question 10:
402 – ( ) = 78 – 6 × 8 ÷ 16.
Find the missing number in the box.

Solution:
402 – ( ) = 78 – 6 × 8 ÷ 16
402 – ( ) = 78 – 48 ÷ 16
402 – ( ) = 78 – 3
402 – ( ) = 75
( ) = 402 – 75
( ) = 327

# 1.2.1 Whole Numbers, PT3 Practice

     
Question 1:
 Solve 8 × 2 ÷ 4 + 12.
 

 Solution:
 
8 × 2 ÷ 4 + 12
 = 16 ÷ 4 + 12
 = 4 + 12
 = 16
 
 
 
      
Question 2:
 Solve 7(6 + 5) – 3(13 – 9).
 

 Solution:
 
7(6 + 5) – 3(13 – 9)
 = 7(11) – 3(4)
 = 77 – 12
 = 65
 
 
 
     
Question 3:
 Solve 64 + (136 – 87) × (28 ÷ 4).
 

 Solution:
 
64 + (136 – 87) × (28 ÷ 4)
 = 64 + 49 × 7
 = 64 + 343
 = 407
 
 
 
    
Question 4:
 Solve 84 ÷ 4 – 9 + 6 × 7
 

 Solution:
 
84 ÷ 4 – 9 + 6 × 7
 = 21 – 9 + 42
 = 12 + 42
 = 54
 
 
 
    
Question 5:
 Solve 92 + 13 × 5 – 42
 

 Solution:
 
92 + 13 × 5 – 42
 = 92 + (13 × 5) – 42
 = 92 + 65 – 42
 = 157 – 42
 = 115