4.6 SPM Practice (Long Questions)


Question 13 (5 marks):
(a) State whether the following statements are true statement or false statement.
( i ) {  }{ S,E,T } ( ii ) { 1 }{ 1,2,3 }={ 1,2,3 }

(b) Diagram 7 shows the first three patterns of a sequence of patterns.

Diagram 7

It is given that the diameter of each circle is 20 cm.
(i) Make a general conclusion by induction for the area of the unshaded region.

(ii)
 Hence, calculate the area of the unshaded region for the 5th pattern.


Solution:
(a)(i) True

(a)(ii) False

(b)(i)
Area of unshaded region (first)
= (20 × 20) – π(10)2
= 400 – 100π
= 100 (4 – π)

Area of unshaded region (second)
= 4 × 100 (4 – π)
= 400 (4 – π)

Area of unshaded region (third)
= 9 × 100 (4 – π)
= 900 (4 – π)
100 (4 – π), 400 (4 – π), 900 (4 – π), …
102 (4 – π), 202 (4 – π), 302 (4 – π), …

General conclusion = n2 (4 – π)
n = 10, 20, 30, …


(b)(ii)

Area of unshaded region (5th)
= 502 (4 – π)
= 2500 (4 – π)


4.6 SPM Practice (Long Questions)


Question 11 (5 marks):
(a) State whether the following compound statement is true or false.
2 > 3 and (–2)3 = –8

(b) Write down two implications based on the following statement:
a > b if and only if a – b > 0

(c) Table 1 shows the number of sides and the number of axes of symmetry for some regular polygons.

Table 1

Make a conclusion by induction by completing the statement in the answer space:
The number of axes of symmetry for a regular polygon with n sides is __________.


Solution:
(a)
Palsu. Nilai bagi 2 adalah kurang daripada 3, 2 < 3.

(b)
Implication 1: Jika a > b, maka a – b > 0
Implication 2: Jika a – b > 0, maka a – b > 0

(c)
The number of axes of symmetry for a regular polygon with n sides is
Number of sides of regular polygon = Number of axes of symmetry of regular polygon



Question 12 (5 marks):
(a) State whether the following statement is true or false.


(b)
 Write down the converse of the following implication:
 

(c)
 Write down Premise 2 to complete the following argument:
Premise 1   :  If x is an odd number, then x is not divisible by 2.
Premise 2   : ………………………………………………………
Conclusion : 24 is not an odd number.

(d)
 Based on the information below, make one conclusion by deduction for the surface area of sphere with radius 9 cm.



Solution:
(a)
True

(b)
If an angle is an acute angle, then the angle lies between 0o and 90o.

(c)
24 is divisible by 2.

(d)
4π(9)2 = 324π
Surface area of the sphere is 324π.


4.6 SPM Practice (Long Questions)


Question 9:
(a) State whether the following statements are true statement or false statement.
( i ) { }{ H,O,T } ( ii ) { 2 }{ 2,3,4 }={ 2,3,4 }

(b) Complete the following statement to form a true statement by using the quantifier ‘all’ or ‘some’.
   ……… factor of 24 are factor of 40

(c) Write down two implications based on the following compound statement.

The perimeter of square ABCD is 60 cm if and only if the side of square ABCD is 15 cm.
(d) It is given that the volume of the sphere is 4 3 π r 3 where r is the radius.
Make one conclusion by deduction for the volume of the sphere with radius 3 cm.

Solution:
(a)(i) True

(a)(ii)
False

(b)    …Some… factor of 24 are factor of 40

(c)(i) If the perimeter of square ABCD is 60 cm, then the side of square ABCD is 15 cm.

(c)(ii)
If the side of square ABCD is 15 cm, then the perimeter of square ABCD is 60 cm.

(d)
4 3 π× 3 3 =36π Volume of the sphere is 36π.    



Question 10:
(a)(i) State whether the following compound statement is true or false.

   All straight lines have positive gradients.
(ii) Write down the converse of the following implication.

If x = 5, then x2 = 25.
(b) Write down Premise 2 to complete the following argument:
Premise 1: If Q is an odd number, then 2 × Q is an even number.
Premise 2: _____________________
Conclusion: 2 × 3 is an even number.

(c) Make a general conclusion by induction for the sequence of numbers 4, 18, 48, 100, … which follows the following pattern.
4 = 1 (2)2
18 = 2 (3)2
48 = 3 (4)2
100 = 4 (5)2
  .
  .
  .

Solution:
(a)(i) False

(a)(ii)
If x2 = 25, then x = 5

(b) Premise 2: 3 is an odd number

(c) n (n + 1)2, where n = 1, 2, 3, …


4.5.1 Argument (Sample Questions)


Example 1:
Complete the conclusion in the following argument:
Premise 1: All regular polygons have equal sides.
Premise 2: ABCD is a regular polygon.
Conclusion:
Solution:
Conclusion: ABCD has equal sides.



Example 2:
Complete the conclusion in the following argument:
Premise 1: If m > 4, then 2m > 8.
Premise 2: 2m < 8
Conclusion:
Solution:
Conclusion: m < 4.


Example 3
:
Complete the premise in the following argument:
Premise 1:
Premise 2: m ×n is not an even number.
Conclusion: m and n are not even numbers.
Solution:
Premise 1: If m and n are even numbers, then m ×n is an even number.
 
 
 
Example 4:
Complete the premise in the following argument:
Premise 1: If x = 3, then x2 = 9.
Premise 2:
Conclusion: x  3
Solution:
Premise 2: x2 ≠ 9.

4.4.1 Implications (Sample Questions)


Example 1:
Write down two implications based on the following statement.
y3 = -125 if and only if y = -5.

Solution
:

Implication 1: If y3 = -125, then y = -5.
Implication 2: If y = -5, then y3 = -125. 



Example 2:
Write down two implications based on the following statement.
8 is a factor of 24 if and only if 24 can be divided exactly by 8.

Solution
:

Implication 1: 8 is a factor of 24 if 24 can be divided exactly by 8.
Implication 2: 24 can be divided exactly by 8 if 8 is a factor of 24.



Example 3:
State the converse of the following statement and hence, determine whether its converse is true or false.
(a) If 2x > 8, then x > 4.
(b) If x is a multiple of 6, then it is a multiple of 3.

Solution
:

(a) Converse implication: If x > 4, then 2x > 8.
 The converse is true.
(b) Converse implication: If x is a multiple of 3, then it is multiple of 6.
 The converse is false. (9 is a multiple of 3 but it is not a multiple of 6) 

4.3 Operations on Statements (Sample Questions 2)


Example 3:
Determine whether each of the following statements is true or false.
(a) × (-4) = -12 and 13 + 6 = 19
(b) 100 × 0.7 = 70 and 12 + (-30) = 18

Solution:
When two statements are combined using ‘and’, a true compound statement is obtained only if both statements are true.
If one or both statements are false, then the compound statement is false.

(a)
Both the statements ‘3 × (-4) = -12’ and ‘13 + 6 = 19’ are true. Therefore, the statement ‘3 × (-4) = -12 and 13 + 6 = 19’ is true.

(b)
The statement ‘12 + (-30) = 18’ is false. Therefore, the statement ‘100 × 0.7 = 70 and 12 + (-30) = 18’ is false.



Example 4:
Determine whether each of the following statements is true or false.
(a) m + m = mor p × p × p = p-3
(b)  64 3 =4 or  27 3 =3

Solution:
When two statements are combined using ‘or’, a false compound statement is obtained only if both statements are false.
If one or both statements are true, then the compound statement is true.

(a) Both the statements ‘m+ m = m2’ and ‘p × p × p= p-3’ are false. Therefore the statement m + m = mor p × p × p = p-3 is false.

(b) The statement  ' 27 3 = 3 '  is true. Therefore, the statement  64 3 =4 or  27 3 =3  is true.

4.3 Operations on Statements

4.3 Operations on Statements (Part 3)

(C) Truth Values of Compound Statements using ‘Or’
 
1. When two statements are combined using ‘or’, a false compound statement is obtained only if both statements are false.
 
2. f one or both statements are true, then the compound statement is true.
 
The truth table:
Let p = statement 1 and q= statement 2.
The truth values for ‘p’ or ‘q’ are as follows:


 
Example 6:
Determine the truth value of the following statements.
(a) 60 is divisible by 4 or 9.
(b) 53 = 25 or 43 = 64.
(c) 5 + 7 > 14 or √9 = 2.
 
Solution:
(a)
60 is divisible by 4  ← (p is true)
60 is divisible by 9  ← (q is false)
Therefore, 60 is divisible by 4 or 9 is a true statement. (‘p or q’ is true)
 
(b)
53 = 25  ← (p is false)
43 = 64  ← (q is true)
Therefore, 53 = 25 or 43 = 64 is a true statement. (‘or q’ is true)
 
(c)
5 + 7 > 14  ← (p is false)
√9 = 2  ← (is false)
Therefore, 5 + 7 > 14 or √9 = 2 is a false statement. (‘p or q’ is false)

4.3 Operations on Statements

4.3 Operations on Statements (Part 2)
(B) Truth Values of Compound Statements using ‘And’
 
4. When two statements are combined using ‘and’, a true compound statement is obtained only if both statements are true.
 
5. If one or both statements are false, then the compound statement is false.
 
The truth table:
Let p = statement 1 and q = statement 2.
The truth values for ‘p’ and ‘q’ are as follows:

 
Example 5:
Determine the truth value of the following statements.
(a) 12 × (–3) = –36 and 15 – 7 = 8.
(b) 5 > 3 and –4 < –5.
(c) Hexagons have 5 sides and each of the interior angles is 90o.
 
Solution:
(a)
12 × (–3) = –36 ← (p is true)
15 – 7 = 8 ← (q is true)
Therefore 12 × (–3) = –36 and 15 – 7 = 8 is a true statement. (‘p and q’ is true)
 
(b)
5 > 3 ← (p is true)
–4 < –5 ← (q is false)
Therefore 5 > 3 and –4 < –5 is a false statement. (‘p and q’ is false)

(c)
Hexagons have 5 sides. ← (p is false)
Each of the interior angles of Hexagon is 90o. ← (is false)
Therefore Hexagons have 5 sides and each of the interior angles is 90o is a false statement. (‘p and q’ is false)

4.6 SPM Practice (Long Questions)


Question 1:
(a) State if each of the following statements is true or false.
 (i) (i)  2 4 =16  and  12÷ 27 3 =3.
 (ii) 17 is a prime number or an even number.

(b) Complete the statement, in the answer space, to form a true statement by 
using the quantifier ‘all’ or ‘some’.

(c) Write down two implications based on the following statement:


A number is a prime number if and only if it is only divisible by 1 and itself.
Solution:
(a)(i) False
(a)(ii) True

(b)   Some   multiples of 3 are multiples of 6.

(c) Implication 1: If a number is a prime number, then it is only divisible by 1 and itself.
 Implication 2: If a number is only divisible by 1 and itself, then it is a prime
 number.


Question 2:
(a) State if each of the following statements is true or false.
  (i)  2 × 3 = 6 or 2 + 3 = 6
  (ii) 2 is a prime number and 5 is an even number.

(b) Write down the converse of the following implication.

  Hence, state whether the converse is true or false.

If x is a multiple of 12,
then x is a multiple of 3.
(c) Complete the premise in the following argument:

Premise 1: All hexagons have six sides
Premise 2: _____________________
Conclusion: ABCDEF has six sides.
Solution:
(a)(i) True
(a)(ii) False

(b) Converse: If x is a multiple of 3, then x is a multiple of 12.
  The converse is false.

(c) Premise 2: ABCDEF is a hexagon.

4.3 Operations on Statements (Sample Questions 1)


Example 1:
Form a compound statement by combining two given statements using the word ‘and’.
(a) × 12 = 36
 7 × 5 = 35

(b)
5 is a prime number.
 5 is an odd number.

(c)
Rectangles have 4 sides.
 Rectangles have 4 vertices.

Solution:

(a) × 12 = 36 and 7 × 5 = 35
(b) 5 is a prime number and an odd number.
(c) Rectangles have 4 sides and 4 vertices.



Example 2:
Form a compound statement by combining two given statements using the word ‘or’.
(a) 16 is a perfect square. 16 is an even number.
(b) 4 > 3.  -5 < -1

Solution:
(a) 16 is a perfect square or an even number.
(b) 4 > 3 or -5 < -1.