Bab 5 Indeks dan Logaritma Posted on May 13, 2016 by user 5.5 Indeks dan Logaritma, SPM Praktis (Soalan Pendek) Soalan 5: Selesaikan persamaan, log 9 ( x−2 )= log 3 2 Penyelesaian: log 9 ( x−2 )= log 3 2 log a b= log c b log c a ⇒ log 3 ( x−2 ) log 3 9 = log 3 2 log 3 ( x−2 ) 2 = log 3 2 log 3 ( x−2 )=2 log 3 2 log 3 ( x−2 )= log 3 2 2 x−2=4 x=6 Soalan 6: Selesaikan persamaan, log 9 ( 2x+12 )= log 3 ( x+2 ) Penyelesaian: log 9 ( 2x+12 )= log 3 ( x+2 ) log 3 ( 2x+12 ) log 3 9 = log 3 ( x+2 ) log 3 ( 2x+12 )=2 log 3 ( x+2 ) log 3 ( 2x+12 )= log 3 ( x+2 ) 2 2x+12= x 2 +4x+4 x 2 +2x−8=0 ( x+4 )( x−2 )=0 x=−4 (tidak diterima) x=2 Soalan 7: Selesaikan persamaan, log 4 x= 3 2 log 2 3 Penyelesaian: log 4 x= 3 2 log 2 3 log 2 x log 2 4 = 3 2 log 2 3 log 2 x 2 = 3 2 log 2 3 log 2 x=2× 3 2 log 2 3 log 2 x=3 log 2 3 log 2 x= log 2 3 3 x=27 Soalan 8: Selesaikan persamaan, 2 log 5 2 = log 2 ( 2−x ) Penyelesaian: 2 log 5 2 = log 2 ( 2−x ) 2= log 5 2. log 2 ( 2−x ) 2= 1 log 2 5 . log 2 ( 2−x ) 2 log 2 5= log 2 ( 2−x ) log 2 5 2 = log 2 ( 2−x ) 25=2−x x=−23