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**Question 6**:

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The mass of a box containing 6 papayas is 21.32 kg. The mass of the box when it is empty is 1.46 kg.

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Calculate the average mass, in g, of a papaya.

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**Solution**:

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Mass of 6 papayas

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= 21.32 – 1.46

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= 19.86 kg

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Average mass of a papaya

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= 19.86 ÷ 6

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= 3.31 kg

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= 3.31 × 1000 g

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= **3310 g**

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**Question 7**:

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Louis bought 600 g of cookies. Dennis bought twice the mass of cookies that Jackson bought. They bought 1.35 kg of cookies altogether. Calculate the mass, in g, of cookies bought by Jackson.

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**Solution**:

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Let Jackson bought *w* g of cookies.

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600 g + 2 × *w* + *w* = 1.35 kg

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600 g + 3*w* = 1.35 kg

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600 g + 3*w* = 1350 g

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3*w* = 1350 g – 600 g

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*w* = 750 g ÷ 3

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*w*** = 250 g**

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**Question 8**:

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If the mass of 4 packets of candies is 2.6 kg, what is the mass of 9 packets of the same candies, in kg?

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**Solution**:

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$\begin{array}{l}\text{Massof4packetsofcandies=2}\text{.6kg}\\ \text{Massof9packetsofcandies}=\frac{2.6}{4}\times 9\\ \text{}=5.85\text{kg}\end{array}$
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**Question 9**:

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It is given that
$\frac{1}{4}$
of fruits is supplied to Juice Stall* A* and
$\frac{2}{7}$
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to Juice Stall* B*. The remaining 133.25 kg is sold to a fruit stall.

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Calculate the mass of fruits that has been supplied to Fruit Stall *B.*

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**Solution**:

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$\begin{array}{l}\frac{1}{4}+\frac{2}{7}=\frac{7}{28}+\frac{8}{28}\\ \text{}=\frac{15}{28}\\ \text{Remainingfruitssoldtofruitstall}\\ =1-\frac{15}{28}\\ =\frac{13}{28}\\ \\ \text{Totalmassoffruits}\\ =\frac{28}{13}\times 133.25\\ =287\text{kg}\\ \\ \text{MassoffruitssuppliedtoJuiceStall}B\\ =\frac{2}{7}\times 287\\ =82\text{kg}\end{array}$
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**Question 10**:

The mixture of metal to produce a piece of 50 sen coin are
$\frac{2}{3}\text{zinc,}\frac{1}{5}\text{nickel}$
and the rest is copper.

If the mass of copper is 1.6 g, find the total mass, in g, of zinc and nickel.

**Solution**:

$\begin{array}{l}\text{Fractionofcopper}\\ =1-\frac{2}{3}-\frac{1}{5}\\ =\frac{15}{15}-\frac{10}{15}-\frac{3}{15}\\ =\frac{2}{15}\\ \\ \text{Portionofcopper=2g}\\ \text{Portionofzincandnickel=13g}\\ \\ 2\leftrightarrow 1.6\text{g}\\ \text{Totalmassofzincandnickel},\\ 13\leftrightarrow \frac{13\times 1.6}{2}=10.4\text{g}\end{array}$