Measures of Dispersion (Part 3)

Measures of Dispersion (Part 3)
7.3 Variance and Standard Deviation

1. The variance is a measure of the mean for the square of the deviations from the mean.

2. The standard deviation refers to the square root for the variance.

(A) Ungrouped Data




Example 1:
Find the variance and standard deviation of the following data.
15, 17, 21, 24 and 31

Solution:
Variance, σ2=x2Nˉx2σ2=152+172+212+242+3125(15+17+21+24+315)2σ2=2492521.62σ2=31.84Standard deviation, σ = varianceσ = 31.84σ = 5.642


(B) Grouped Data (without Class Interval)




Example 2:
The data below shows the numbers of children of 30 families:

Number of child
2
3
4
5
6
7
8
Frequency
6
8
5
3
3
3
2




Find the variance and standard deviation of the data.


Solution:
Mean ˉx=fxf=(6)(2)+(8)(3)+(5)(4)+(3)(5)+(3)(6)+(3)(7)+(2)(8)6+8+5+3+3+3+2=12630=4.2fx2f=(6)(2)2+(8)(3)2+(5)(4)2+(3)(5)2+(3)(6)2+(3)(7)2+(2)(8)26+8+5+3+3+3+2=63430=21.13Variance, σ2=fx2fˉx2σ2=21.1334.22σ2=3.493Standard deviation, σ = varianceσ = 3.493σ = 1.869


(C) Grouped Data (with Class Interval)




Example 3:

Daily Salary(RM)
Number of workers
10 – 14
40
15 – 19
25
20 – 24
15
25 – 29
12
30 – 34
8
Find the mean of daily salary and its standard deviation.

Solution:

Daily Salary (RM)
Number of workers, f
Midpoint, x
fx
fx2
10 – 14
40
12
480
5760
15 – 19
25
17
425
7225
20 – 24
15
22
330
7260
25 – 29
12
27
324
8748
30 – 34
8
32
256
8192
Total
100

1815
37185
Mean ˉx=fxfMean of daily salary=1815100=18.15Variance, σ2=fx2fˉx2Standard deviation, σ = varianceσ2=3718510018.152σ2=42.43σ = 42.43σ = 6.514