9.6 SPM Practice (Long Questions)


Question 5:
A (53o N, 84o E), B (53o N, 25o W), C and D are four points on the surface of the earth. AC is the diameter of the parallel of latitude 53o N.

(a)
State the location of C.

(b)
Calculate the shortest distance, in nautical mile, from A to C measured along the surface of the earth.

(c)
Calculate the distance, in nautical mile, from A due east B measured along the common parallel of latitude.

(d)
An aeroplane took off from B and flew due south to D. The average speed of the flight was 420 knots and the time taken was 6½ hours.
Calculate
(i) the distance, in nautical mile, from B to D measured along the meridian.
(ii) the latitude of D.


Solution:
(a)
Latitude of C = 53o N
Longitude of C = (180o – 84o) E = 96o E
Therefore location of C = (53o N, 96o E)

(b)
Shortest distance from A to C
= (180 – 53 – 53) x 60
= 74 x 60
= 4440 nautical miles

(c)
Distance from A to B
= (84 – 25) x 60 x cos 53o
= 59 x 60 x cos 53o
= 2130.43 nautical miles

(d)
( i ) Distance travel from B to D =420×6 1 2  Distance travelled  = average speed × time taken  =2730 nautical miles ( ii ) Difference in latitude between B to D = 2730 60 = 45.5 o Latitude of D=( 53 o 45.5 o )N = 7.5 o N