Definite Integrals

3.4a Definite Integral of f(x) from x=a to x=b



Example:
Evaluate each of the following.
  (a)01(3x22x+5)dx(b)20(2x+1)3dx

Solution:
  (a)01(3x22x+5)dx=[3x332x22+5x]01=[x3x2+5x]01=0[(1)3(1)2+5(1)]=0(115)=7(b)20(2x+1)3dx=[(2x+1)44(2)]20=[(2x+1)48]20=[(2(2)+1)48][(2(0)+1)48]=625818=78


Short Question 2 – 4


Question 2:
Given that  Given that4(1+x)4dx=m(1+x)n+c,
find the values of m and n.

Solution:
4(1+x)4dx=m(1+x)n+c4(1+x)4dx=m(1+x)n+c4(1+x)33(1)+c=m(1+x)n+c43(1+x)3+c=m(1+x)n+cm=43,n=3



Question 3:
Given 212g(x)dx=4, and 21[mx+3g(x)]dx=15.Find the value of constant m.

Solution:
21[mx+3g(x)]dx=1521mxdx+213g(x)dx=15[mx22]21+321g(x)dx=15[m(2)22m(1)22]+32212g(x)dx=152m12m+32(4)=15given212g(x)dx=432m+6=1532m=9m=9×23m=6



Question 4:
Givenddx(2x3x)=g(x), find21g(x)dx.

Solution:
Givenddx(2x3x)=g(x)g(x)dx=2x3xThus,21g(x)dx=[2x3x]21=2(2)322(1)31=41=3

Long Question 6


Question 6:
Diagram below shows part of the curve   y=2(3x2)2  which passes through (1, 2).


(a) Find the equation of the tangent to the curve at the point B.
(b) A region is bounded by the curve, the x-axis and the straight lines x = 2 and x = 3.
(i) Find the area of the region.
(ii) The region is revolved through 360° about the x–axis. Find the volume generated, in terms of p.

Solution:
(a)
y=2(3x2)2=2(3x2)2dydx=4(3x2)3(3)dydx=12(3x2)3dydx=12(3(1)2)3,x=1dydx=12y2=12(x1)y2=12x+12y=12x+14


(b)(i)

Area =32ydx=322(3x2)2dx=322(3x2)2dx=[2(3x2)11(3)]32=[23(3x2)]32=[23[3(3)2]][23[3(2)2]]=221+16=114unit2


(b)(ii)
Volume generated=πy2dx=π324(3x2)4dx=π324(3x2)4dx=π[4(3x2)33(3)]32=π[49(3x2)3]32=π[49[3(3)2]3][49[3(2)2]3]=π(43087+4576)=315488πunit3

3.5 Integration as the Summation of Areas

3.5 Integration as the Summation of Areas

(A) Area of the region between a Curve and the x-axis.



Area of the shaded region;  A=baydx


(B) Area of the region between a curve and the y-axis.


Area of the shaded region;  A=baxdy


(C) Area of the region between a curve and a straight line.


Area of the shaded region;  A=baf(x)dxbag(x)dx

SPM Practice 2 (Question 1 – 3)

Question 1:
Reduce non-linear relation, y=pxn1, where k and n are constants, to linear equation.  State the gradient and vertical intercept for the linear equation obtained.
[Note : Reduce No-linear function to linear function]

Solution:


 

Question 2:
The diagram shows a line of best fit by plotting a graph of  y2against x.

  1. Find the equation of the line of best fit.
  2. Determine the value of
    1. x when y = 4,
    2. y when x = 25.
Solution:



 

Question 3:
The diagram shows part of the straight line graph obtained by plottingy against x2.

Express y in terms of x.

Solution:



 

SPM Practice 3 (Linear Law) – Question 1


Question 1 (10 marks):
Use a graph to answer this question.
Table 1 shows the values of two variables, x and y, obtained from an experiment.
The variables x and y are related by the equation yh=hkx , where h and k are constants.


(a) Plot xy against x, using a scale of 2 cm to 1 unit on the x-axis and 2 cm to 5 units on the xy-axis.
Hence, draw the line of best fit.

(b) Using the graph in 9(a), find
(i) the value of h and of k,
(ii) the correct value of y if one of the values of y has been wrongly recorded during the experiment.

Solution: 
(a)




(b)
yh=hkxxyhx=hkxy=hx+hkY=mX+CY=xy, m=h, C=hk


(b)(i)
m=36.55.1h=36.55.1h=7.157h=51.22C=4hk=4k=4hk=451.22k=0.0781


(b)(ii)
xy=213.5y=21y=213.5=6.0Correct value of y is 6.0.


Tips To Reduce Non-Linear Function To Linear Function

Tips:
(1)  The equation must have one constant (without x and y).
(2)  X and Y cannot have constant, but can have the variables (for example x and y).
(3)  m and c can only have the constant (for example a and b), cannot have the variables x and y.


Examples
(1)
X and Y cannot have constant, but can have the variables (for example x and y)



(2)
 m and c can only have the constant (for example a and b), cannot have the variables x and y





SPM Practice 2 (Linear Law) – Question 4

Question 4
The table below shows the corresponding values of two variables, x and y, that are related by the equation y=qx+pqx , where p and q are constants.


One of the values of y is incorrectly recorded.
(a) Using scale of 2 cm to 5 units on the both axis, plot the graph of xy against x2  .  Hence, draw the line of best fit

(b) Use your graph in (a) to answer the following questions:
(i) State the values of y which is incorrectly recorded and determine its actual value.
(ii) Find the value of p and of q.

Solution
Step 1 : Construct a table consisting X and Y.


Step 2 : Plot a graph of Y against X, using the scale given and draw a line of best fit


Steps to draw line of best fit - Click here

(b) (i) State the values of y which is incorrectly recorded and determine its actual value.


Step 3 : Calculate the gradient, m, and the Y-intercept, c, from the graph

Step 4 : Rewrite the original equation given and reduce it to linear form

Step 5 : Compare with the values of m and c obtained, find the values of the unknown required

Distance Between Two Points

Distance between point A(x1,y1) and point is B(x2,y2) given by

(x1x2)2+(y1y2)2


 

Reduce Non-Linear Function To Linear Function – Examples (G) To (L)

Examples:
Reduce each of the following equations to the linear form. Hence, state the gradient and the Y-intercept of the linear equations in terms of  a and b.
(g)  kx2+ty2=x  
(h)  y=xp+qx  
(i)  hy=x+kx  
(j)  y=abx  
(k)  y=axb  
(l)  y=abx+1

[Note :
X and Y cannot have constant, but can have the variables (for example x and y)
 m and c can only have the constant (for example a and b), cannot have the variables x and y]

Solution: